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A particle of mass 2 kg moves in simple ...

A particle of mass `2 kg` moves in simple harmonic motion and its potential energy `U` varies with position `x` as shown. The period of oscillation of the particle is

A

`(2pi)/(5)s`

B

`2sqrt(2pi)/(5)s`

C

`sqrt(2pi)/(5)s`

D

`(4pi)/(5)s`

Text Solution

Verified by Experts

The correct Answer is:
D
`(1)/(2) kA^(2) = 1.0`
`(1)/(2)k (0.4)^(2) = 1.0`
or `k = 12.5` or `(25)/(2)N//m`
`T = 2pi sqrt ((m)/(k)) = 2pi sqrt ((2)/((25)/(2))) = (4pi)/(5)s`
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Knowledge Check

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