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Find the period of oscillation of the sy...

Find the period of oscillation of the system shown in figure.

Text Solution

Verified by Experts

The correct Answer is:
B

Resultant of `k` and `k` is `2k`. Then, resultant of `2k` and `2k` is `k`.
Now `T = 2pi sqrt((m)/(k)) `
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Knowledge Check

  • The period of the free oscillations of the system shown here if mass m_(1) is pulled down a little and force constant of the spring is k and masses of the fixed pulleys are negligible, is

    A
    `T = 2pi sqrt((m_(1) + m_(2))/(k))`
    B
    `T = 2pi sqrt((m_(1) + 4m_(2))/(k))`
    C
    `T = 2pi sqrt((4m_(1) + m_(2))/(k))`
    D
    `T = 2pi sqrt((3m_(1) + m_(2))/(k))`
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