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A simple pendulum with a bob of mass m i...

A simple pendulum with a bob of mass `m` is suspended from the roof of a car moving with horizontal acceleration a

A

The string makes an angle of `tan^(-1)(a//g)` with the vertical

B

The string makes an angle of `sin^(-1)((a)/(g))` with the vertical

C

The tension in the string is `msqrt(a^(2) + g^(2))`

D

The tension in the string is `msqrt(g^(2) - a^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A, C

`tan theta = (ma)/(mg) = (a)/(g)`

`theta = tan^(-1)((a)/(g))`
`T = F_(net)`
` = msqrt(a^(2) + g^(2))`
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Knowledge Check

  • A simple pendulum with a bob of mass m is suspended from the roof of a car moving with a horizontal acceleration a.

    A
    The string makes an angle of `tan^(-1)(a//g)` with the vertical
    B
    The string makes an angle of `tan^(-1) (1-(a)/(g))` with the vertical
    C
    The tension in the string is `msqrt(a^(2)+g^(2))`
    D
    The tension in the string is `m sqrt(g^(2)-a^(2))`
  • A simple pendulum with a bob of mass m is suspended from the roof of a car moving with a horizontal accelertion a. The angle made by the string with verical is

    A
    `tan^(-1)((a)/(g))`
    B
    `tan^(-1)(1-(a)/(g))`
    C
    `cos^(-1)((a)/(g))`
    D
    `sin^(-1)((a)/(g))`
  • A pendulum with a bob of 0.1kg is suspended from the roof of a car which is moving with an acceleration of 5 m//s^(2) relative to the ground towards right . An observer travelling in the car experiences a pseudo force acting on the bob equal to :

    A
    1.0 N downwards
    B
    1.0 N upwards
    C
    0.5 N towards right
    D
    0.5 N towards left
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