Home
Class 12
MATHS
Statement-1: The smallest positive integ...

Statement-1: The smallest positive integer n such that n! can be expressed as a product of n-3 consecutive integers, is 6.
Statement-2: Product of three consecutive integers is divisible by 6.

A

Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1

B

Statement-1 is true, statement-2 is true, statement-2 is not a correct explanation for statement-1

C

Statement-1 is true, statement-2 is false

D

Statement-1 is false, statement-2 is true

Text Solution

Verified by Experts

The correct Answer is:
B

Statement-1 is true
`therefore6!=720=8xx9xx10` i.e., product off 6-3=3 consecutive integers and statement-2 is also true, but statement-2 is not a correct explanation for statement-1.
Promotional Banner

Topper's Solved these Questions

  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS|Exercise Exercise (Subjective Type Questions)|17 Videos
  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|28 Videos
  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS|Exercise Permutations and Combinations Exercise 5: Matching Type Questions|1 Videos
  • PARABOLA

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|36 Videos
  • PROBABILITY

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|55 Videos

Similar Questions

Explore conceptually related problems

" The product of three consecutive positive integers is divisible by "

prove that the product of three consecutive positive integers is divisible by 6.

Prove that the product of two consecutive positive integers is divisible by 2 .

Prove that the product of 2n consecutive negative integers is divisible by (2n)!

Prove that one of every three consecutive positive integers is divisible by 3.

Prove that one of every three consecutive positive integers is divisible by 3.

The product of n consecutive natural numbers is always divisible by