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Tangent to the curve y=x^2+6 at a point ...

Tangent to the curve `y=x^2+6` at a point `(1,7)` touches the circle `x^2+y^2+16x+12y+c=0 `at a point `Q`, then the coordinates of `Q` are (A) `(-6,-11)` (B) `(-9,-13)` (C) `(-10,-15)` (D) `(-6,-7)`

A

(-6,-11)

B

(-9,-13)

C

(-10,-15)

D

(-6,-7)

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Tangent to the curve y=x^(2)+6 at a point P(1, 7) touches the circle x^(2)+y^(2)+16x+12y+c=0 at a point Q. Then the coordinates of Q are

    A
    `(-6,-11)`
    B
    `(-9,-13)`
    C
    `(-10,-15)`
    D
    `(-6,-7)`
  • Tangent to the parabola y=x^(2)+6 at (1, 7) touches the circle x^(2)+y^(2) +16x +12y+c=0 at the point

    A
    (-6, -9)
    B
    (-13, -9)
    C
    (-6, -7)
    D
    (13, 7)
  • The tangent at (1,7) to the curve x^(2)=y-6 touches the circle x^(2)+y^(2)+16x+12y+c=0 at

    A
    (6,7)
    B
    (-6,7)
    C
    (6,-7)
    D
    (-6,-7)
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