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1.0 g of metal nitrate gave 0.86 g of me...

1.0 g of metal nitrate gave 0.86 g of metal carbonate. Calculate the Equivalent weight of metal.

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Let the equivalent weight of metal `=E`
Ew of metal nitrate`=Ew of M+EwNO_3^(ɵ)=E+62`
Equivalent weight of metal carbonate
`=` Equivalent weight of metal
`+` Equivalent weight of `CO_3^(2-)`
`=E+(60)/(2)=E+30`
`therefore("Ew of M nitrate")/("Ew of M carbonate")=("Weight of M nitrate")/("weight of M sulphate")`
`(E+62)/(E+30)=(1.0)/(0.86)`
`thereforeE=166.57`
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