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Balance the following equatio in basic m...

Balance the following equatio in basic medium
`NH_3+O_2toNO_2H_2O`
In the commercial preparation of `HNO_3` by Ostwald process, the above reaction is carried out directly in the process, The above reaction is carried out directly in the gaseous state. Explian why the same equation describes the direct reaction and the reaction in basic medium?

Text Solution

Verified by Experts

`2H_2O+cancel(4e^(-))+underset(2x=0)(O_2)toundersetunderset(2x=-4)(2x+2=-2)(cancel(2overset(ɵ)(O))H+cancel(2overset(ɵ)(O))H]xx5`
`5cancel(overset(ɵ)(O))H+undersetunderset(x=-3)(x+3=0)(NH_3)toundersetunderset(x=2)(x-2=0)(NO)+5cancel(e^(-))+4H_2O]xx4`
`underline(5O_2+4NH_3to4NO+6H_2O)`
When the same products are produced from a given set of reactants, the equation will be the same no matter what the medium is.
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Knowledge Check

  • Consider the follwing reaction in basic medium : NH_3 + O Cl^(-) rarr N_2 H_4 + Cl^(-) The coefficient fo N_2H_4 in the balanced equation will be .

    A
    `4`
    B
    `3`
    C
    `1`
    D
    `2`

  • A reversible reaction H_(2)+Cl_(2)hArr2HCl is carried out in one litre flask. If the same reaction is carried out in two litre flask, the equlibrium constant will be

    A
    Decreased
    B
    Doubled
    C
    Halved
    D
    Same

  • BeC_(2)+H_(2)O rarr The products of above reaction are :

    A
    `Be(OH)_(2)` and `CO_(2)`
    B
    `Be(OH)_(2)` and `CH_(4)`
    C
    `Be(OH)_(2)` and `H_(2)C=CH_(2)`
    D
    `Be(OH)_(2)` and `HC-=CH`