A solution of `KMnO_(4)` containing `3gL^(-1)` is used to titrate `H_(2)O_(2)` solution containing `2gL^(-1)` What volume of `KMnO_(4)` will be required to react with 10 " mL of " `H_(2)O_(2)`? Also find strength of `H_(2)O_(2)` solution in terms of available oxygen.

Explanation

`N_(1)(KMnO_(4))=(3)/(31.6)`
`N_(2)(H_(2)O_(2))=(2)/(17)=0.1176`
`N_(1)V_(1)=N_(2)V_(2)`
`V_(1)=(0.1176xx20xx31.6)/(3)=24.78 mL`
`1 NH_(2)O_(2)=5.6` volume `O_(2)`
`0.1174 N of H_(2)O_(2)=5.6xx0.1176=0.66V`