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60ml of mixture of equal volumes of Cl(2...

`60ml` of mixture of equal volumes of `Cl_(2)` and an oxide of chloine, i.e., `Cl_(2)O_(n)` was heated and then cooled back to the original temperature. The resulting gas mixture was found to have volume of `75ml`. On treatment with `KOH` solution, the volume contracted to `15ml`. Assume that all measurements are made at the same temperature and pressure. Deduce the value of `n` in `Cl_(2)O_(n)`. The oxide of `Cl_(2)` n heating decomposes quantiatively to `O_(2)` and `Cl_(2)`.

Text Solution

Verified by Experts

Let the oxide is `Cl_(x).O_(y)`.
`Cl_(x)O_(y)to(x)/(2)Cl_(2)+(y)/(2)O_(2)`
Volume of `Cl_(x)O_(y)=` volume of `Cl_(2)=3 mL`
After cooling, volume `=75mL`
This corresponds to volume of `Cl_(2)` initially plus volume of `Cl_(2)` produced and `O_(2)` produced.
`thereforeV_(Cl_(2))+V_(Cl_(2))` (produced)`+V_(O_(2))=75mL`
`V_(Cl_(2))` (produced) `+V_(O_(2))=75-30=45mL`
(Since `V_(Cl_(2))` initiall `=30mL`)
NaOH apart from `CO_(2)` also absorbs `Cl_(2)`. So after `NaOH` treatment, the residual volume corresponds to the volume of `O_(2)(=15mL)`
`therefore` Volume of `Cl_(2)=45-15=30mL`
Volume of `Cl_(2)=30xx(x)/(2)=30impliesx=2`
Volume of `O_(2)=30xx(y)/(2)=15impliesy=1`
Hence formula of chlorid is `Cl_(2)O`.
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Knowledge Check

  • 100 ml of a mixture of methane and acetylene was exploded with excess of oxygen. After cooling to room temperature the resulting gas mixture was passed through KOH when a reduction of 135 ml in volume was noted. The composition of the hydrocarbon mixture by volume at the same temperature and pressure will be

    A
    65% `CH_4, 35% C_2H_2`
    B
    `35% CH_4, 65% C_2H_2`
    C
    `25% CH_4,75% C_2H_2`
    D
    `85% CH_4, 15% C_2H_2`

  • 20 ml of a mixture of CO_(2) & C_(2)H_(4) was mixed with excess of O_(2) gas & was exploded. On bringing the solution back to the original room temperature a contraction of 12 ml was observed . What is the volume percentage of CO_(2) in the original mixture.

    A
    0.06
    B
    0.14
    C
    0.7
    D
    0.3

  • 20 ml of a mixture of CO_2 and C_2H_4 was mixed with excess of O_2 gas and was exploded.On bringing the solution back to the original room temperature a contraction of 12 ml was observed. What is the volume percentage of CO_2 in the original mixture ?

    A
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    B
    `14%`
    C
    `70%`
    D
    `30%`