50 g caustic soda is completely converted into sodium chlorate and sodium chloride by the action of chlorine What weight of manganese dioxide and what volume of HCl (containing `300gL^(-1)`) were used for the production of necessary chlorine?

Explanation

`underset(87g)(MnO_(2))+underset(4xx36.5g)(4HCl)toMnCl_(2)+underset(71g)(Cl_(2))+2H_(2)O`
`underset(3xx71g)(3Cl_(2))+underset(6xx40g)(6NaOH)to5NaCl+NaClO_(3)+3H_(2)O`
for 50 g of NaOH, the weight of `Cl_(2)` required
`=(3xx71xx50)/(6xx40)=44.25g`
Weight of HCl required`=(4xx36.5xx44.25)/(71)=91g`
Weight of `MnO_(2)` required`=(87xx91)/(4xx36.5)=54.226`g