What Volume of 0.1 M `KMnO_(4)` in acidic medium is required for complete oxidation of 100 " mL of " 0.1 M `FeCO_(2)O_(4)` and 100 " mL of " 0.1 m ferric oxalate separately.

Options

A. 60 " mL of " `KMnO_(4)` with `FeC_(2)O_(4)`
B. `40 " mL of " KMnO_(4)` with `FeC_(2)O_(4)`
C. `40 " mL of " KMnO_(4)` with ferric oxalate
D. `120 " mL of " KMnO_(4)` with ferric oxalate

Answer

A, D

Explanation

Case I: `underset((n=5))(MnO_(4)^(ɵ))-=underset((n=3))(FeC_(2)O_(4))`
`[{:(overset(2+)(Fe)tooverset(+3)(Fe)+e^(-)),(C_(2)O_(4)^(2-)to2CO_(2)+2e^(-)):}]n=3`
`Vxx0.1xx5-=100xx0.1xx3`
`V=60mL`
Case II:
`underset((n=5))(MnO_(4)^(ɵ))-=underset((n=6))(Fe_(2)(C_(2)O_(4))_(3))` [oxidation reducing agent]
`[Fe^(3+)` does not oxidise `3C_(2)O_(4)^(2-)to6CO_(2)+6e^(-)]`
`V=0.1xx5-=100xx0.1xx6`
`V=120mL`