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N-factor for the following reaction is ...

N-factor for the following reaction is
`FeS_(2)toFe_(2)O_(3)+SO_(2)`

A

8

B

9

C

10

D

11

Text Solution

Verified by Experts

The correct Answer is:
D
`overset(+2)(Fe)overset(-1xx2)/(S_(2))tooverset(+3xx2)(Fe_(2))overset(-2xx3)(O_(3))+overset(+4-2xx2)(SO_(2))`
`underset(2x=4)(2Fe^(2+))overset(0)tounderset(2x=6)(Fe_(2)^(3+)+2e^(-)]n=(2)/(2)=1`
`{:(underset(2x=-2)(S_(2)^(2-))toundersetunderset(2x=18)(2x-8=0)(2SO_(2))+10e^(-)]n=10`
Total n factor `=10+1=11`
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Knowledge Check

  • FeS_(2) is converted into Fe_(2)O_(3) according to the following equation 4FeS_(2) +xO_(2) to 2Fe_(2)O_(3) + ySO_(2) x and y used in the equation have the values .

    A
    10 and 8
    B
    11 and 8
    C
    5 and 4
    D
    6 and 7

  • The values of heat of formation of SO_(2) and SO_(3) are -298.2 kJ and -98.2 kJ . The heat of reaction of the following reaction will be SO_(2)+(1)/(2)O_(2)rarrSO_(3)

    A
    `-200` kJ
    B
    `-356.2` kJ
    C
    `+200 kJ`
    D
    `-396.2 kJ`

  • The equivalent weight of FeS_(2) in the following reaction is FeS_(2)+O_(2) rarr Fe^(+3)+SO_(2)

    A
    `"Mol. wt"/1`
    B
    `"Mol. wt"/7`
    C
    `"Mol. wt"/11`
    D
    `"Mol. wt"/9`

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