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If 3.7 g of a gas at 25^(@)C occupies th...

If `3.7 g` of a gas at `25^(@)C` occupies the same volume as `0.814 g` of hydrogen at `17^(@)C` and at the same pressure, then what is the molecular weight of the gas?

Text Solution

Verified by Experts

`PV=nRT`
`P` and `V` are the same.
So, `n_(1)T_(1)=nT_(2)`
or `(w_(1))/(M_(1))T_(1)=(w_(2))/(M_(2))T_(2)`
or `(3.7)/(M_(1))xx298=(0.184)/(2)xx290`
or `M_(1)=41.33 g`
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Knowledge Check

  • 3.7 gm of gas at 25^(@)C occupied the same volume as 0.184 gm of hydrogen at 17^(@)C and at the same pressure. What is the molecular mass of the gas ?

    A
    `82.66`
    B
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    B
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    D
    40.2

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    `88.0`
    B
    `44.0`
    C
    `28.0`
    D
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