If calcium crystallizes in `bc c` arrangement and the radius of `Ca` atom is `96 pm`, then the volume of unit cell of `Ca` is

Options

A. `10.9 xx 10^(-36) m^(3)`
B. `10.9 xx 10^(-30) m^(3)`
C. `21.8 xx 10^(-30) m^(3)`
D. `21.8 xx 10^(-36) m^(3)`

Answer

B

Explanation

For bcc latice, `sqrt(3)a = 4R rArr a = (4 xx 96)/(sqrt(3))` pm
`= 22.17` pm
(where `R` is the radius of `Ca` atom)
Volume of unit cell `= a^(3) = (22.17 xx 10^(-12))^(3) = m^(3)`
`= 10.9 xx 10^(-30) m^(3)`