An aqueous solution at -2.55^(@)C. What ...

An aqueous solution at `-2.55^(@)C`. What is its boiling point `(K_(b)^(H_(2)O)=0.52 K m^(-1)`,`K_(f)^(H_(2)O)=1.86 K m^(-1)`?

Text Solution

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The correct Answer is:

`DeltaT_(f)=2.55^(@)C = K_(f).m :. M=2.55/K_(f)`
`DeltaT_(b)=K_(b)m rArr DeltaT_(b)`
`=2.55 xx K_(b)/K_(f)=2.55 xx 0.52/1.86^(@)C)=0.7^(@)C`
`rArr T_(b) = 100 + 0.7 =100.7^(@)C`

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