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The resistance of a conductivity cell fi...

The resistance of a conductivity cell filled with `0.1 M KCl` solution is `100 Omega`. If `R` of the same cell when filled with `0.02 M KCl` solution is `520 Omega`, calculate the conductivity and molar conductivity of `0.02 M KCl` solution. The conductivity of `0.1 M KCl `solution is `1.29 S m^(-1)`.

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To solve the problem, we need to calculate the conductivity and molar conductivity of a 0.02 M KCl solution based on the given data. Let's break it down step by step. ### Step 1: Calculate the Cell Constant (G*) We are given the resistance (R1) of a 0.1 M KCl solution and its conductivity (k1). The formula for conductivity is: \[ k = \frac{G^*}{R} \] ...
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Resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohm. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. [Given : Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ]

Resistance of a conductivity cell filled with 0.1 mol L^(-1) KCl solution is 100Omega . If the resistance of the same cell when filled with 0.02 mol L^(-1) KCl solution is 520Omega , calculate the conductivity and molar conductivity of 0.02 M KCl solution. The conductivity of 0.1 M KCl solution is 1.29S/m.

Knowledge Check

  • Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. What is the conductivity of 0.02 M KCl solution ?

    A
    0.452 S `m^(-1)`
    B
    0.215 S `m^(-1)`
    C
    0.614 S `m^(-1)`
    D
    0.433 S `m^(-1)`

  • Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. SI unit for conductivity of a solution is

    A
    S `m^(-1)`
    B
    `Sm^(2)mol^(-1)`
    C
    `mol" "cm^(-3)`
    D
    `S" "cm^(2)mol^(-1)`

  • Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. What will happen to the conductivity of the cell with the dilution ?

    A
    First decreases then increases
    B
    Increases
    C
    First increases then decreases
    D
    Decreases

    • Similar Questions

    Explore conceptually related problems

    Resistance of a conductivity cell filled with 0.1 M KCl is 100 ohm. If the resistence of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. Conductivity of 0.1 KCl solution is 1.29xx10^(-2)" ohm "^(-1)cm^(-1) .

    (a) Define the following terms : (i) Limiting molar conductivity, (ii) Fuel cell (b) Resistance of a conductivity cell filled with 0.1 molL^(-1)KCl solution is 100 Ohm. If the resistance of the same cell when filled with 0.2 mol L^(-1)KCl solution is 520 Ohm , calculate the conductivity and molar conductivity of 0.2 mol L^(-1) KCl solution. The conductivity of 0.1 mol L^(-1) KCl solution is 1.29xx10^(-1) Scm^(-1) .

    Resistance of a conductivity cell filled with 0.1 mol L^(-1) KCl solution is 100 ohms. If the resistance of the same cell filled with 0.02 mol L^(-1) KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 mol L^(-1) KCl solution. The conductivity of 0.1 mol L^(-1) KCl solution is 1.29 xx 10^(-2) S cm^(-1)

    Calculating conductivity and molar conductivity: Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If the resistance of the same cell when filled with 0.02 M KCl solutions 520 Omega and the conductivity of 0.1 KCl solution is 1.29 S m , calculate the conductivity and moalr conductivity of 0.02 M KCl solution. Strategy : Calculate the cell constant with the help of 0.01 M KCl solution (both R and kappa are Known). Use the cell constant to determine the conductivity of 0.02 M KCl solution and finally find its molar conductivity using the molarity

    Read the passage given below and answer the question: The cell constant is usually determined by measuring the resistance of the cell containing a solution whose conductivity is already known. For this purpose, we generally use KCl solutions whose conductivity is known accurately at various concentrations and at different temperatures. consider the resistance of a conductivity cell filled with 0.1 M KCl solution is 200 Ohm. if the resistance of the same cell when filled with 0.02 M KCl solution is 420 Ohm. (Conductivity of 0.1 M KCl solution is 1.29 S m^(-1) ). Q. Which of the following is not true ? The conductivity of solutions of different electrolytes in the same solvent and at a given temperature differs due to

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