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During the electrolysis of acidified wa...

During the electrolysis of acidified water, `O_(2)` gas is formed at the anode. To produce `O_(2)` gas at the anode at the rate of `0.224 Ml` per second at `STP`, the current passed is

A

`0.224A`

B

`2.24 A`

C

`9.64 A`

D

`3.86 A`

Text Solution

Verified by Experts

The correct Answer is:
d
First method
At anode `(` oxidation `):`
`H_(2)O rarr 2H^(o+)+2e^(-)+(1)/(2) O_(2)(g)`
`2F=2xx96500C=(1)/(2) mol O_(2)at STP. `
`=(22.4)/(2)=11.2L of O_(2)`
`11.2xx10^(3) mL =2 xx 96500C`
`0.224 mL of O_(2)` per second `=(96500xx0.224mL)/(11.2 xx 10^(3)mL)`
`=3.86 A`
Second methode
`1F=96500C=1 Eq of O_(2)=(22.4 )/(4) =5.6 L`
`5.6 xx 10^(3)mL =96500C`
`0.224 mL ` per second of `O_(2)=(96500xx0.224)/(5.6xx10^(3)mL)`
`=3.86A`
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Knowledge Check

  • During electrolysis of acidified water, O_(2) gas is formed at the anode . To produce O_(2) gas at the anode at the rate of 0.224mL per second at STP , current passed is

    A
    `0.224A`
    B
    `2.24A`
    C
    `9.65A`
    D
    `3.86A`

  • in the electrolysis method of acidified water to give O_(2) , the cathode used is

    A
    graphite
    B
    lead
    C
    platinum
    D
    Nickel

  • When electrolysis is carried out on water, __________ gas is liberated at the anode.

    A
    Hydrogen
    B
    Oxygen
    C
    Nitrogen
    D
    Ozone

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    In electrolysis of water, Name the gas collected at cathode and anode.

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