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Consider the isoelectronic species, Na^(...

Consider the isoelectronic species, `Na^(+),Mg^(2+),F^(-)` and `O^(2-)`. The correct order of increasing length of their radii is:

A

`F^(-)ltO^(2-)ltMg^(2+)ltNa^(+)`

B

`Mg^(2+)ltNa^(+)ltF^(-)ltO^(2-)`

C

`O^(2-)ltF^(-)ltNa^(+)ltMg^(2+)`

D

`O^(2-)ltF^(-)ltMg^(2+)ltNa^(+)`

Text Solution

Verified by Experts

The correct Answer is:
B

For isoelectronic species,ionic radii decrease with increase in nuclear charge(I.e.,no. of protons).Thus,the cation with greater +Ve charge will have a smaller radius and the anion with greater -Ve charge will have a larger radius.Thus,the correct order of increasing ionic radii is `Mg^(2+)ltNa^(+)ltF^(-)ltO^(2-)`
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