In a clock, what is the time period of meeting of the minute hand and the second hand ?

Explanation

`omega_(min) = (2 pi)/(60) rad min^-1, omega_(sec) = (2 pi)/(1) rad min^-1`
`theta_(sec) - theta_(min) = 2 pi`
(for second and minute hand to meet again)
`(omega_(sec) - v_(min)) t = 2 pi`
`2 pi (1 - 1//60) t = 2 pi`
`rArr t = (60)/(59) min`.
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