The standard potentials of some electrodes are as follows. Arrange the metals in an increasing order of their reductiong power.
`1)K^(+)//K=-2.93V" "2)Ag^(+)//Ag =0.80V" "3) Cu^(2+)//Cu=0.34V`
`4)Mg^(2+)//Mg =-2.37V" "5)Cr^(3+)//Cr =-0.74C" "6)Fe^(+)//Fe =-0.44V`

Explanation

Given
`{:(E_(0)"of cell" K ^(+)//K , =-2.93V),(Ag^(+)//Ag, =0.80V),(Cu^(+2)//Cu, =0.34V):}{:(Mg^(+2) //Mg , =-2.37V),(Cr^(+3)//Cr, =-0.74V),(Fe^(+2)//Fe, =-0.44V):}`
Lower the reduction potential values indicates high reducing power and high value indicates the high oxidising power.
So, increasing order of the given cells reducing power is
`Ag lt Cu lt Fe lt Cr lt Mg lt K.`