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The percentage of quantity of a radioact...

The percentage of quantity of a radioactive material that remains after 5 half-lives will be .

A

`31%`

B

`3.125%`

C

`0.3%`

D

`1%`

Text Solution

Verified by Experts

The correct Answer is:
b
`(N)/(N_(0))=(1)/(2^(5T//T))`
`(N)/(N_(0)) =(1)/(2^(5))`
`:. (N)/(N_(0)) xx 100=(100)/(32)=3.125`.
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