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.(92)U^(238) changes to .(85)At^(210) by...

`._(92)U^(238)` changes to `._(85)At^(210)` by a series of `alpha`-and `beta`-decays. Find the number of `alpha`-decays undergone `("an integer")`.

Text Solution

Verified by Experts

The correct Answer is:
7
x and y are number of `alpha`-decays and `beta`-decays respectively.
`92-2x+y=85`
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Knowledge Check

  • If ._(92)U^(238) changes to ._(85)At^(210) by a series of alpha -and beta -decays, the number of alpha and beta -decays undergone is .

    A
    `7 and 5`
    B
    `7 and 7`
    C
    `5 and 7`
    D
    `7 and 9`

  • If ._(92)U^(235) assumed to decay only by emitting two alpha -and one beta -particles, the possible product of decays is

    A
    `._(89)Ac^(231)`
    B
    `._(89)Ac^(235)`
    C
    `._(89)Ac^(236)`
    D
    `._(89)Ac^(227)`

  • A nuclide A undergoes alpha -decay and another nuclides B undergoes beta -decay

    A
    All the `alpha`-particles emitted by `A` will have almost the same speed
    B
    The `alpha`-particles emitted by `A` may have widely different speed.
    C
    All the `beta^(-)` particle emitted by `B` will have almost three same speed
    D
    The `beta^(-)` particles emitted by `B` may have widely different speeds