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In a certain region of space, there exists a uniform and constant electric field of strength E along x-axis and uniform constant magnetic field of induction B along z-axis. A charge particle having charge q and mass m is projected with speed v parallel to x-axis from a point (a, b, 0). When the particle reaches a point 2a, `b//2`, 0 its speed becomes 2v. Find the value of electric field strength of m, v and co-ordinates.

A

`3/2 (mv^2)/(qa)`

B

`(mv^2)/(qa)`

C

`(2mv^2)/(qBa)`

D

`3/2 vB`

Text Solution

Verified by Experts

The correct Answer is:
A

change in kinetic energy is only due to work done by electric field. Hence work done by electric field is change on KE:
`qEa=1/2m[(2v)^(2)-v^(2)] implies E+(3mv^(2))/(2qa)`.
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