Home
Class 11
CHEMISTRY
The H-O-H bond angle in the water molecu...

The `H-O-H` bond angle in the water molecule is `105^@` , the`H -O` bond distance being `0.94 Å`, The dipole moment for the moelcule is `1.85D`. Calculate the charge on the oxygen atom .

A

`2 xx 10^(-10)` esu

B

`3.28 xx 10^(-10)` esu

C

`3.22 xx 10^(-10)` esu

D

`1.602 xx 10^(-19)` esu

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY|Exercise Exercises Single Correct (Hybridisation)|33 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY|Exercise Exercises Single Correct (Bond Angle)|10 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY|Exercise Exercises Single Correct (Chemical Bonding)|46 Videos

  • ATOMIC STRUCTURE

    CENGAGE CHEMISTRY|Exercise Concept Applicationexercise(4.3)|19 Videos

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Archives (Subjective)|11 Videos

Similar Questions

Explore conceptually related problems

The H-O-H bond angle in water is

The H-O-H angle in water molecule is about

The net dipole moment of H_(2)O molecule is

The H-O-H bond in water molecule is

The O-O-H bond angle in H_2 O_2 is ?

Knowledge Check

  • The H-O-H bond angle in water molecule is about:

    A
    `105^(@)`
    B
    `109^(@)`
    C
    `180^(@)`
    D
    `90^(@)`

  • The H-O-H bond angle in water is

    A
    `109.5^@`
    B
    `107^@`
    C
    `102^@`
    D
    `104.5^@`

  • The H-O-H angle in water molecule is about

    A
    90°
    B
    180°
    C
    102°
    D
    105°