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The H-O-H bond angle in the water molecu...

The `H-O-H` bond angle in the water molecule is `105^@` , the`H -O` bond distance being `0.94 Å`, The dipole moment for the moelcule is `1.85D`. Calculate the charge on the oxygen atom .

A

`2 xx 10^(-10)` esu

B

`3.28 xx 10^(-10)` esu

C

`3.22 xx 10^(-10)` esu

D

`1.602 xx 10^(-19)` esu

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The H-O-H bond angle in water molecule is about:

    A
    `105^(@)`
    B
    `109^(@)`
    C
    `180^(@)`
    D
    `90^(@)`

  • The H-O-H bond angle in water is

    A
    `109.5^@`
    B
    `107^@`
    C
    `102^@`
    D
    `104.5^@`

  • The H-O-H angle in water molecule is about

    A
    90°
    B
    180°
    C
    102°
    D
    105°

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    The O-O-H bond angle in H_(2)O_(2) is

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