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The coordination number of Ni^(2+) is 4 ...

The coordination number of `Ni^(2+)` is 4
`NiCI_(2) + KCN` (excess)rarr`A` (cyano complex)
`NiCI_(2)+conc.HCI` (excess) rarr `B` (Chloro complex)
The `IUPAC` name of `A` and `B` are .

A

potassium tetracyanonickelate(II),potassium tetrachloronickelate(II) .

B

tetracyanopotassiumnickelate(II)tetrrachloropotassiumnickelate(II) .

C

tetracyanonickel(II) tetrachloronickel(II)

D

potassium tetracyanonickel(II),tetracholoronickel(II) .

Text Solution

Verified by Experts

The correct Answer is:
a

`NiCI_(2)+4KCNrarrK_(2)[Ni(CN)_(4]+2KCI`
`A is K_(2)[Ni(CN)_(4)]`
Potassium tetracyanonickelate(II)
`K_(2)[Ni(CN)_(4)]+4HCI(conc)rarr,K_(2)[Ni(CN)_(4)]+4HCN`
`B is K_(2)[NiCI_(4)]`
Potassium tetrachloridonickelate(II) .
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Knowledge Check

  • The coordination number of Ni^(2+) is 4 NiCl_(2)+KCN ("excess")rarr A("cyano complex") A + conc. HCl ("excess")rarr B ("chloro complex") The IUPAC names of A and B are

    A
    Potassium tetracyanonickeltate(II), potassium tetrachloronickeltate(II)
    B
    Tetracyanopotassium nickelate(II), tetrachloro-potassiumnickelate(II)
    C
    Tetracyanonickel(II), tetrachloronickel(II)
    D
    Potassium tetracyanonickel(II), potassium tetrachloronickel(II)
  • The coordination number of Ni^(2+) is 4. NiCl_(2) + KCN ("excess") rarr A ("cyano comples") NiCl_(2) + conc. HCl ("excess") rarr B ("chloro complex") The hybridisation of A and B are

    A
    `dsp^(2), sp^(3)`
    B
    `sp^(3), sp^(3)`
    C
    `dsp^(2), dsp^(2)`
    D
    `sp^(3)d^(2), d^(2) sp^(3)`
  • The coordination number of Ni^(2+) 4 NiCl_(2) + KCN (excess) to A (cyano complex) NiCl_(2) + Conc. HCI (excess) to B (chloro complex) QThe IUPAC name of A and B are

    A
    Potassium tetracyanonickelate (Il), potassium tetrachloronickelate (II)
    B
    Tetracyanopotassiumnickelate (II), teterachlorpotassiumnickelate (II)
    C
    Nickel (II), tetrachloronickel (II)
    D
    Potassium tetracyanonickel (II), potassium tetrachloronickel (II)
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