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If the normal at t(1) on the parabola y...

If the normal at `t_(1) ` on the parabola `y^(2)=4ax` meet it again at `t_(2)` on the curve then `t_(1)(t_(1)+t_(2))+2` =

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The correct Answer is:
`rArr t_(1)^(2)+t_(1)t_(2)+2=0`
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