A block of mass `m`m remains stationary on a fixed inclined plane of inclination `theta` . If `mu`= coefficient of static friction the reaction of ground on the block is:

Options

A. `mug costheta`
B. `mgcostheta`
C. `mgsintheta`
D. `mg darr`

Answer

D

Explanation

As block is stationary on inclined plane.
Hence friction force `=mgsintheta`
and normal reaction applied on the block `=mgcostheta`
Hence net reation on the block applied by inclied plane
`sqrt((mgsintheta)^(2)+(mgcostheta)^(2))=mg` upward