Consider three cases, same spring is attached with `2kg` , `3kg` and `1kg` blocks as shown in figure. If `x_(1)` , `x_(2)` , `x_(3)` be the extensions in the spring in the three cases, then.

Options

A. `x_(2)gtx_(1)gtx_(3)`
B. `x_(1)gtx_(2)gtx_(3)`
C. `x_(1)=0` , `x_(3)gtx_(2)`
D. `x_(3)gtx_(2)gtx_(1)`

Answer

A

Explanation

If `T_(1),T_(2),T_(3)` , are the tension in the strings in the three cases, we have
In case I: `T_(1)=(2m_(1)m_(2)g)/(m_(1)+m_(2))=(2xx2xx2g)/((2+2))=20N`
In case II: `T_(2)(2xx3xx2g)/((3+2))=24N`
`T_(3)=(2xx3xx2g)/((1+2))=(40)/(3)N`
At `T=K_(x)`
or `xpropT` here `T_(2)gtT_(1)gtT_(3)`
Hence, `x_(2)gtx_(1)gtx_(3)` .