A body of mass `2kg` is moving towards east with a uniform speed of `2ms^(-1)` . A force of `3N` is applied to it towards north. The magnitude of the displacement of the body `2s` after the application of force is.

Options

A. `4m`
B. `5m`
C. `6m`
D. `7m`

Answer

B

Explanation

`m=2kg`
`vec(v)=2hatim//s`
`vec(F)=3hatjN`
`vec(a)=(vec(F))/(m)=(3)/(2)hatjm//s^(2)`
Since `vec(s)=vec(vt)+(1)/(2)vec(a)t^(2)`
`vec(s)=(2hati)2+(1)/(2)((3)/(2))(4)hatj`
`vec(s)4hati+3hatj`
`|vec(s)|=sqrt(4^(2)+3^(2))` = 5m