Home
Class 11
PHYSICS
Assertion: The time period of revolution...

Assertion: The time period of revolution of a satellite close to surface of earth is smaller then that revolving away from surface of earth.
Reason: The square of time period of revolution of a satellite is directely proportioanl to cube of its orbital radius.

A

If both the assertion and reason are true and reason is a true explantion of the assertion.

B

If both the assertion and reason are true but the reason is not true the correct explantion of the assertion.

C

If the assertion is true but reason false

D

If both the assertion and reason are false.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the assertion and reason question, we need to analyze both statements and determine their validity based on the principles of gravitation and orbital mechanics. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that the time period of revolution of a satellite close to the surface of the Earth is smaller than that of a satellite revolving away from the surface of the Earth. - This implies that satellites in lower orbits (closer to Earth) have shorter orbital periods compared to those in higher orbits. 2. **Understanding the Reason**: - The reason provided states that the square of the time period (T²) of revolution of a satellite is directly proportional to the cube of its orbital radius (r³). - This relationship can be expressed mathematically as: \[ T^2 \propto r^3 \] - According to Kepler's Third Law of Planetary Motion, this relationship holds true for any satellite orbiting a central body. 3. **Applying the Concepts**: - For a satellite close to the Earth's surface, the orbital radius (r) is approximately equal to the Earth's radius (R) since the height (h) above the surface is negligible. - For a satellite further away, the orbital radius is greater than R (i.e., \( r = R + h \) where h is significant). - Since \( T^2 \propto r^3 \), if the orbital radius (r) increases, the time period (T) will also increase. 4. **Conclusion**: - Therefore, the assertion is correct: the time period of a satellite close to the surface of the Earth is indeed smaller than that of a satellite revolving away from the surface. - The reason is also correct: the square of the time period is directly proportional to the cube of the orbital radius. - Thus, both the assertion and the reason are true, and the reason correctly explains the assertion. ### Final Answer: - Both the assertion and the reason are true, and the reason correctly explains the assertion.

To solve the assertion and reason question, we need to analyze both statements and determine their validity based on the principles of gravitation and orbital mechanics. ### Step-by-Step Solution: 1. **Understanding the Assertion**: - The assertion states that the time period of revolution of a satellite close to the surface of the Earth is smaller than that of a satellite revolving away from the surface of the Earth. - This implies that satellites in lower orbits (closer to Earth) have shorter orbital periods compared to those in higher orbits. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    A2Z|Exercise NEET Questions|42 Videos
  • GRAVITATION

    A2Z|Exercise AIIMS Questions|21 Videos
  • GRAVITATION

    A2Z|Exercise Problems Based On Mixed Concepts|29 Videos
  • GENERAL KINEMATICS AND MOTION IN ONE DIMENSION

    A2Z|Exercise Chapter Test|30 Videos
  • KINETIC THEORY OF GASES AND THERMODYNAMICS

    A2Z|Exercise Chapter Test|29 Videos

Similar Questions

Explore conceptually related problems

Show that the square of the period or revolution of a satellite is directly proportional to the cube of the orbital radius.

Which has longer period of revolution, a satellite revolving close or away from the surface of earth?

Knowledge Check

  • Time period of revolution of poalr satellite is aroung

    A
    6 minutes
    B
    100 minutes
    C
    8 hours
    D
    24 hours
  • Assertion : The time period of a satellite revolving very close to the surface of earth is less. Reason : According to Kepler's law, square of time period of revolution is directly proportional to the cube of semi-major axis.

    A
    If both assertion and reason are correct and reason is a correct explanation of the assertion.
    B
    If both assertion and reason are correct but reason is not the correct explanation of assertion.
    C
    If assertion is correct but reason is incorrect.
    D
    If assertion is incorrect but reason is correct.
  • Time period of a satellite to very close to earth s surface, around the earth is approximately

    A
    1.42 h
    B
    2.42 h
    C
    24 h
    D
    0.72 h
  • Similar Questions

    Explore conceptually related problems

    Time period of pendulum, on a satellite orbiting the earth, is

    Assertion : Geostationary satellites appear fixed from any point on earth. Reason : The time period of geostationary satellite is

    The period of revolution of an earth satellite close to surface of earth is 90min. The time period of aother satellite in an orbit at a distance of three times the radius of earth from its surface will be

    A satellite is revolving in circular orbit of radius r around the earth of mass M. Time of revolution of satellite is

    Assertion: Geostationary satellite appear fixed from any point on earth. Reason: The time period of geostationary satellite is 24 hrs