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A body is fired with a velocity of magni...

A body is fired with a velocity of magnitude `sqrt(gR) lt Vsqrt(2gR)` at an angle of `30^(@)` with the radius vector of earth. If at the highest point the speed of the body is `V//4`, the maximum height attained by the body is equal to:

A

`V^(2)//8g`

B

`R`

C

`sqrt(2)R`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A

Coservation of angular momentum of the body about `O` yields

`(mVsin30^(@))R=mV'(R+h)`
`V/2R=V/4(R+h) [ :. V'=V/4]`
`:. h=R`
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Knowledge Check

  • A body is fired with a velocity of magnitude sqrt(gR)ltVltsqrt(2gR) at an angle of 30^@ with the radius vector of the earth. If at the highest point, the speed of the body is V//4 , the maximum height attained by the body is equal to

    A
    `(V^(2))/(8g)`
    B
    `R`
    C
    `sqrt(2)R`
    D
    none of these
  • If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10m//s)

    A
    `11.25m`
    B
    `16.2m`
    C
    `24.5m`
    D
    `7.62m`
  • A body is projected at an angle of 30^(@) with the horizontal with momentum P .At its highest point the magnitude of the momentum is:

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    `sqrt3/2P`
    B
    `2/sqrt3P`
    C
    `P`
    D
    `P/2`
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