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Time period (T) and amplitude (A) are sa...

Time period `(T)` and amplitude `(A)` are same for two particle which undergoes `SHM` along the same line. At one particular instant one particle is at phase`(3pi)/(2)`and the other is at zero, while moving in the same direction. Find the time at which they will cross each other

A

`4T//2`

B

`3T//8`

C

`3T//4`

D

`3T//7`

Text Solution

Verified by Experts

The correct Answer is:
B
At phase `3pi//2, (omegat + phi) = 3pi//2`
`x_(1) = A sin'(3pi)/(2) = -A`
`x_(2) = 0`
So at `t = 0 , x_(1) = -A cos omega` and `x_(2) = A sin omega t`
` x_(1) =x_(2)`
`-cos omegat = sin omegat`
`tan omegat = -1`
`omega t = (2pi)/(4)`
`((2pi)/(T)) t = (3pi)/(4)`
`t = 3T//8`
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Knowledge Check

  • Two particles undergo SHM along the same line with the same time period (T) and equal amplitude (A). At a particular instant one particle is at x = -A and the other is at x = 0. They move in the same direction. They will cross each other at

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    A
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    B
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