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A body is performing simple harmonic mot...

A body is performing simple harmonic motion with amplitude A and time period `T` variation of its acceleration `(f)` with time`(t)` is shown in figure If a line `x` velocity of the body is `x` which of the following graph is correct?

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A

Acceleration of a particle executing `SHM` is always directed toward the mean position and its magnitude is velocity properition is that it displacement from mean position.
Since acceleration of it’s the particle at initial moment a maximumm position and is negative the particle is at right execute position is at right exectude position at this moment.
when the particle is relassed it closed it start is move in the left it mean velocity start value and its magnitude becomes maximum position at mean position (at `t = T//4)`.
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Knowledge Check

  • A body is performing simple harmonic motion. Then its

    A
    average total energy per cycle is equal to its maximum kinetic energy.
    B
    average kinetic energy per cycle is equal to half of its maximum kinetic energy.
    C
    average total energy per cycle is equal to half of its malximum kinetic energy.
    D
    None of these.
  • A simple harmonic motino has amplitude A and time period T. The maxmum velocity will be

    A
    `4AT`
    B
    `(2A)/(T)`
    C
    `2pi sqrt((A)/(T)`
    D
    `(2piA)/(T)`
  • A body is performing simple harmonic motion of amplitude A and time period T. The figure shown position-time graph of the body . At any time t, acceleration of the body is f, then which of the following graphs is/are appropriate?

    A
    B
    C
    D
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