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A transverse wave is propagating along +...

A transverse wave is propagating along `+x` direction. At `t=2` sec the particle at `x=4`m is at `y=2` mm. With the passage of time its `y` coordinate increases and reaches to a maximum of 4 mm. The wave equation is (using `omega` and `k` with their usual meanings)

A

`y=4sin[omega(t+2)+k(x-2)+(pi)/(6)]`

B

`y=4sin[omega(t+2)+k(x)+(pi)/(6)]`

C

`y=4sin[omega(t-2)-k(x-4)+(5pi)/(6)]`

D

`y=4sin[omega(t-2)-k(x-4)+(pi)/(6)]`

Text Solution

Verified by Experts

The correct Answer is:
D

SHM equation of the particle at `x=4` is
`y=4sin[omega(t+2)+(pi)/(6)]`
Wave equation, replacing t by `[t-((x-4)/(v))]` is
`y=4sin(omega(t-((x-4))/(v)-2)+(pi)/(6))`
`=4sin[omega(t-2)-k(x-4)+(pi)/(6)]`
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Knowledge Check

  • A wave is propagating in positive x- direction. A time t=0 its snapshot is taken as shown. If the wave equation is y=A sin(omegat-Kx+phi) , then phi is

    A
    `phi=0`
    B
    `phi-=pi`
    C
    `phi=pi//2`
    D
    `phi=3pi//2`
  • A plane electromagnetic wave propagating in the x-direction has wavelength of 6.0 mm . The electric field is in the y-direction and its maximum magnitude of 33 Vm^(-1) . The equation for the electric field as function of x and l is

    A
    `11 sin pi(t-x//c)`
    B
    `33 sin pi xx 10^(11)(t-x//c)`
    C
    `33 sin pi(t-x//c)`
    D
    `11 sin pi xx 10^(11) (t-x//c)`
  • A transverse wave propagating along x-axis is represented by : y(x,t) = 8 sin (0.5 pi x - 4 pi t -(pi)/(4)) where x is in metres and t is in seconds . The speed of the wave is

    A
    `4 pi m//s `
    B
    `0.5 pi m//s `
    C
    `(pi)/(4) m//s `
    D
    `8 m//s `
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