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Two sources of sound A and B produces th...

Two sources of sound `A` and `B` produces the wave of `350 Hz`. They vibrate in the same phase. The particle `P` is vibrating under the influence of these two waves, if the amplitudes at the point P produced by the two waves is `0.3mm` and `0.4mm` then the resultant amplitude of the point `P` will be when `AP-BP=25cm` and the velocity of sound is `350m//sec`.

A

`0.7mm`

B

`0.1mm`

C

`0.2mm`

D

`0.5mm`

Text Solution

Verified by Experts

The correct Answer is:
D
`lamda=(v)/(n)=(350)/(350)=1m=100cm`
Also path difference `(Delta x)` between the waves at the point of observation is `AP-BP=25cm`. Hence `Delta phi=(2pi)/(lamda)(Delta x)=(2pi)/(1)xx((25)/(100))=(pi)/(2)`
`impliesA=sqrt((a_1)^2+(a_2_^2))=sqrt((0.3)^2+(0.4)^2)=0.5mm`
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Knowledge Check

  • Two sources of sound A and B produce the wave of 350 Hz ,they vibrate in the same phase.The particle P is vibrating under the influence of these two wave.If the amplitudes at the point P Produced by the two waves is 0.3 mm and 0.4 mm ,then the resultant amplitude of the point P will be [Given AP -BP = 25 cm and the velocity of sound is 350 m/s ]

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    0.7 mm
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    0.1mm
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    0.2mm
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    0.5mm

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