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The two nearest harmonics of a tube clos...

The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system?

A

`20 Hz`

B

`30 Hz`

C

`40 Hz`

D

`10 Hz`

Text Solution

Verified by Experts

The correct Answer is:
A
Two successive frequencies of closed pipe
`(nv)/(4l)=220`
`((n+2)v)/(4l)=260`
Dividing (ii) by (i) we get
`((n+2))/(n)=(260)/(220)=(13)/(11)impliesn=11`
so from (i), `(11xxv)/(4l)=220`
`implies(v)/(4l)=20Hz`
So fundamental frequency `=20Hz`
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