If two liquids of same volume but different densities `rho_1` and `rho_2` are mixed, then the density of the mixture is:

Options

A. `rho=(rho_1+rho_2)/(2)`
B. `rho=(rho_1+rho_2)/(2rho_1rho_2)`
C. `rho=(2rho_1rho_2)/(rho_1+rho_2)`
D. `rho=(rho_1rho_2)/(rho_1+rho_2)`

Answer

A

Explanation

As `M_1=Vrho_1`,`M_2=Vrho_2`,
mass of the mixture`=M_1+M_2=Vrho_1+Vrho_2=V(rho_1+rho_2)`, volume of the mixture, `V+V=2V`
Hence, density of the mixture, `rho=(V(rho_1+rho_2))/(2V)=(rho_1+rho_2)/(2)`