How many `176 Omega` resistors (in parallel) are required to carry 5 A in 220 V line ?

Explanation

Here, `I = 5 A, V = 220 V`.
Resistance required in the circuit, `R = (V)/(I) = (220 V)/(5 A) = 44 Omega`
Resistance of each resistor, `r = 176 Omega`
If `n` resistors, each of resistance `r`, are connected in parallel to get the required resistance `R`, then `R = ( r)/(n)`
or `44 Omega = (176 Omega)/(n)` or `n = (176 Omega)/(44 Omega) = 4`.