Time period of an oscillating drop of radius r, density `rho` and surface tension S is `t = K sqrt((rho r^3)/(S))`. Check the correctness of this relation

Explanation

To check the correctness of the given relation \( t = K \sqrt{\frac{\rho r^3}{S}} \) using dimensional analysis, follow these steps:

1. **Identify the dimensions of each quantity:**
- Time period \( t \): [T]
- Density \( \rho \): [M L\(^{-3}\)]
- Radius \( r \): [L]
- Surface tension \( S \): [M T\(^{-2}\)]

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