To find the value of 'g' by using a simple pendulum, the following observations were made: Length of the thread, `I =(100+- 0.1)cm` Time period of oscillation, `T = (2+-0.1)s` Calculate the maximum permissible in measurement of 'g' which quanitiy should be measured more accurately and why ?

Explanation

`Here, I = (100 +- 0.1)cm T=(2+- 0.1)s , g= ?`
From ` T =2pi sqrt((I)/(g)), g= (4pi^2l)/(T^2)`
`(Deltag)/(g) =+-((DeltaI)/(I) + ( 2DeltaT)/(T)) =+-((0.1)/(100)+(2xx0.1)/(2)) =+- 0.001 + 0.1 =+- 0.101`
`Detlag = +-0.101g = +-xx0.101xx9.8m//s^2 = +-0.9889m//s^2 = +- 1.0m//s^2`
In the calculation of `(Deltag)/(g),((DeltaT)/(T))` is taken twice. Therefore, time period of pendulum must be measured
more accurately.