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arg(bar(z))+arg(-z)={{:(pi",","if arg (z...

`arg(bar(z))+arg(-z)={{:(pi",","if arg (z) "lt 0),(-pi",", "if arg (z) "gt 0):},"where" -pi lt arg(z) le pi`.
If `arg(z) gt 0`, then arg (-z)-arg(z) is equal to

A

`-pi`

B

`-(pi)/2`

C

`pi/2`

D

`pi`

Text Solution

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A
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If arg(z) lt 0, then find arg(-z) -arg(z) .

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Knowledge Check

  • If arg (z) lt 0 then arg (-z) - arg (z) =

    A
    `pi`
    B
    `- pi`
    C
    `- (pi)/(2)`
    D
    `(pi)/(2)`

  • arg(bar(z))+arg(-z)={{:(pi",","if arg (z) "lt 0),(-pi",", "if arg (z) "gt 0):},"where" -pi lt arg(z) le pi . If arga(4z_(1))-arg(5z_(2))=pi, " then " abs(z_(1)/z_(2)) is equal to

    A
    1
    B
    1.25
    C
    1.5
    D
    2.5

  • arg ( bar(z)) is equal to

    A
    `pi `- arg (z)
    B
    `2 pi -`arg (z)
    C
    `pi +` arg (z)
    D
    `2pi + ` arg (z)

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