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bb"Statement-1" 3+7i gt 2+4i, " where " ...

`bb"Statement-1" 3+7i gt 2+4i, " where " i=sqrt(-1).`
`bb"Statement-2 " 3 gt 2 " and " 7 gt 4`

Answer

Step by step text solution for bb"Statement-1" 3+7i gt 2+4i, " where " i=sqrt(-1). bb"Statement-2 " 3 gt 2 " and " 7 gt 4 by MATHS experts to help you in doubts & scoring excellent marks in Class 12 exams.

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Knowledge Check

  • Statement-1: 0 lt x lt y rArr "log"_(a) x gt "log"_(a) y, where a gt 1 Statement-2: "When" a gt 1, "log"_(a) x is an increasing function.

    A
    Statement-1 is True, Statement-2 is true, Statement-2 is a correct explanation for Statement-1.
    B
    Statement-1 is True, Statement-2 is true, Statement-2 is NOT a correct explanation for Statement-1.
    C
    Statement-1 is True, Statement-2 is False.
    D
    Statement-1 is False, Statement-2 is True.

  • The connective in the statement 2 + 7 gt 9 or 2+ 7 lt 9 is

    A
    and
    B
    or
    C
    `gt `
    D
    `lt`

  • Statement-1: 3^("log"_(2) 7) -7^("log"_(2)3) = 0 Statement-2: x^("log"_(a)y) = y^("log"_(a)x), " where "x gt 0, y gt 0" and "a gt 0, a ne 1

    A
    Statement-1 is True, Statement-2 is true, Statement-2 is a correct explanation for Statement-1.
    B
    Statement-1 is True, Statement-2 is true, Statement-2 is NOT a correct explanation for Statement-1.
    C
    Statement-1 is True, Statement-2 is False.
    D
    Statement-1 is False, Statement-2 is True.

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    Let f(theta)=(sin^(2)theta cos theta)/((sin theta+cos theta))-(1)/(4)tan(pi/4-theta), forall theta in R-{npi-pi/4}, n in I. bb"Statement I" The largest and smallest value of f(theta) differ by 1/sqrt(2) bb"Statement II "asinx+bcosx+c in [c-sqrt(a^(2)+b^(2)),c+sqrt(a^(2)+b^(2))], forall x in R, " where " a,b,c in R.

    f is a function defined on the interval [-1,1] such that f(sin2x)=sinx+cosx. bb"Statement I" If x in [-pi/4,pi/4] , then f(tan^(2)x)=secx bb "Statement II" f(x)=sqrt(1+x), forall x in [-1,1]

    bb"Statement I" The period of f(x)=2cos""1/3(x-pi)+4sin""1/3(x-pi) " is " 3pi . bb"Statement II" If T is the period of f(x), then the period of f(ax+b) is T/abs(a) .

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