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If the pair of lines ax^2+2(a+b)xy+by^2=...

If the pair of lines `ax^2+2(a+b)xy+by^2=0` lie along diameters of a circle and divide the circle into four sectors such that the area of one of the sectors is thrice the area of another sector then

A

`3a^2+2ab+3b^2=0`

B

`3a^2+10ab+3b^2=0`

C

`3a^2-2ab+3b^2=0`

D

`3a^2-10ab+3b^2=0`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If the pair of lines ax^(2)+2(a+b)xy+by^(2)=0 lie along diameters of a circle and divide the circle into four section such that the area of one of the sector is thrice theara of another sector then

    A
    `3a^(2)-10ab+3b^(2)=0`
    B
    `3a^(2)-2ab+3b^(2)=0`
    C
    `3a^(2)+10ab+3b^(2)=0`
    D
    `3a^(2)+2ab+3b^(2)=0`
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