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If the differential equation of the fami...

If the differential equation of the family of curve given by `y=Ax+Be^(2x),` where A and B are arbitary constants is of the form
`(1-2x)(d)/(dx)((dy)/(dx)+ly)+k((dy)/(dx)+ly)=0,` then the ordered pair (k,l) is

A

(2,-2)

B

(-2,2)

C

(2,2)

D

(-2,-2)

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Knowledge Check

  • The differential equation of the family of curves y=k_(1)x^(2)+k_(2) is given by (where, k_(1) and k_(2) are arbitrary constants and y_(1)=(dy)/(dx), y_(2)=(d^(2)y)/(dx^(2)) )

    A
    `y_(1)=x^(2)y_(2)`
    B
    `(y_(1))^(2)=xy_(2)`
    C
    `xy_(2)=y_(1)`
    D
    `y_(1)y_(2)=x`

  • The degree of the differential equation ((d^2y)/(dx^2))^2+((dy)/(dx))^2="sin "((dy)/(dx)) is

    A
    1
    B
    2
    C
    3
    D
    not defined

  • The differential equation x(dy)/(dx)+(3)/((dy)/(dx))=y^(2)

    A
    is of order 1
    B
    is of degree 2
    C
    is linear
    D
    is non-linear

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