The Graham's law states that ''at constant pressure and temperature the rate of diffusion or effusion of a gas is inversely proportional to the squar root of its density Rate of diffusion `prop (1)/(sqrt(d))`
If `r_(1)` and `r_(2)` represent the rates of diffusion of two gases and `d_(1)` and `d_(2)` are their respective densities, then
`r_(1)/(r_(2))=sqrt((d_(2))/(d_(1)))`
`r_(1)/(r_(2)) =sqrt((M_(2))/(M_(1))) xx P_(1)/(P_(2))`
`(V_(1)xxt_(2))/(V_(2)xxt_(1)) = sqrt((d_(2))/(d_(1))) = sqrt((M_(2))/(M_(1)))`
`V prop n` (where n is no of moles)
`V_(1) prop n_(1)` and `V_(2) prop n_(2)`
If some moles of `O_(2)` diffuse in 18 sec and same moles of other gas diffuse in `45sec` then what is the molecular weight of the unknown gas ? .
The Graham's law states that ''at constant pressure and temperature the rate of diffusion or effusion of a gas is inversely proportional to the squar root of its density Rate of diffusion `prop (1)/(sqrt(d))`
If `r_(1)` and `r_(2)` represent the rates of diffusion of two gases and `d_(1)` and `d_(2)` are their respective densities, then
`r_(1)/(r_(2))=sqrt((d_(2))/(d_(1)))`
`r_(1)/(r_(2)) =sqrt((M_(2))/(M_(1))) xx P_(1)/(P_(2))`
`(V_(1)xxt_(2))/(V_(2)xxt_(1)) = sqrt((d_(2))/(d_(1))) = sqrt((M_(2))/(M_(1)))`
`V prop n` (where n is no of moles)
`V_(1) prop n_(1)` and `V_(2) prop n_(2)`
If some moles of `O_(2)` diffuse in 18 sec and same moles of other gas diffuse in `45sec` then what is the molecular weight of the unknown gas ? .
If `r_(1)` and `r_(2)` represent the rates of diffusion of two gases and `d_(1)` and `d_(2)` are their respective densities, then
`r_(1)/(r_(2))=sqrt((d_(2))/(d_(1)))`
`r_(1)/(r_(2)) =sqrt((M_(2))/(M_(1))) xx P_(1)/(P_(2))`
`(V_(1)xxt_(2))/(V_(2)xxt_(1)) = sqrt((d_(2))/(d_(1))) = sqrt((M_(2))/(M_(1)))`
`V prop n` (where n is no of moles)
`V_(1) prop n_(1)` and `V_(2) prop n_(2)`
If some moles of `O_(2)` diffuse in 18 sec and same moles of other gas diffuse in `45sec` then what is the molecular weight of the unknown gas ? .
A
`\(45^(2))/(18^(2)) xx 32`
B
`\(18^(2))/(45^(2)) xx 32`
C
`(18^(2))/(45^(2)xx32)`
D
`(45^(2))/(18^(2)xx32)`
Text Solution
Verified by Experts
`(r_(O_(2)))/(r_(X)) =sqrt((M_(X))/(M_(O_(2))))`
Volume are in same ratio, the no. of moles
`(n//18)/(n//45)=sqrt((M_(X))/(32))`
`(45)/(18) sqrt((M_(X))/(32)),:.M_(X) =(45^(2))/(18^(2)) xx 32 =200` .
Volume are in same ratio, the no. of moles
`(n//18)/(n//45)=sqrt((M_(X))/(32))`
`(45)/(18) sqrt((M_(X))/(32)),:.M_(X) =(45^(2))/(18^(2)) xx 32 =200` .
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The Graham's law states that ''at constant pressure and temperature the rate of diffusion or effusion of a gas is inversely proportional to the squar root of its density Rate of diffusion prop (1)/(sqrt(d)) If r_(1) and r_(2) represent the rates of diffusion of two gases and d_(1) and d_(2) are their respective densities, then r_(1)/(r_(2))=sqrt((d_(2))/(d_(1))) r_(1)/(r_(2)) =sqrt((M_(2))/(M_(1))) xx P_(1)/(P_(2)) (V_(1)xxt_(2))/(V_(2)xxt_(1)) = sqrt((d_(2))/(d_(1))) = sqrt((M_(2))/(M_(1))) V prop n (where n is no of moles) V_(1) prop n_(1) and V_(2) prop n_(2) 2 g of hydrogen diffuse from a container in 10 minutes How many grams of oxygen would diffuse through the same container in the same time under similar conditions ? .
The Graham's law states that ''at constant pressure and temperature the rate of diffusion or effusion of a gas is inversely proportional to the squar root of its density Rate of diffusion prop (1)/(sqrt(d)) If r_(1) and r_(2) represent the rates of diffusion of two gases and d_(1) and d_(2) are their respective densities, then r_(1)/(r_(2))=sqrt((d_(2))/(d_(1))) r_(1)/(r_(2)) =sqrt((M_(2))/(M_(1))) xx P_(1)/(P_(2)) (V_(1)xxt_(2))/(V_(2)xxt_(1)) = sqrt((d_(2))/(d_(1))) = sqrt((M_(2))/(M_(1))) V prop n (where n is no of moles) V_(1) prop n_(1) and V_(2) prop n_(2) The time taken for a certain volume of gas X to diffuse through a small hole is 2 minutes It takes 5.65 minutes for oxygen to diffuse under the simillar conditions The molecular weight of X is .
Knowledge Check
If two planets of radii R_(1) and R_(2) have densities d_(1) and d_(2) , then the ratio of their respective acceleration due to gravity is
If two planets of radii R_(1) and R_(2) have densities d_(1) and d_(2) , then the ratio of their respective acceleration due to gravity is
A
`R_(1)d_(1):R_(2)d_(2)`
B
`R_(1)^(2)d_(1):R_(2)^(2)d_(2)`
C
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D
`R_(1)d_(1)^(2):R_(2)^(2)d_(2)^(2)`
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