One litre of `O_(2)` and one litre of `h_(2)` are taken in a vessel of 2 litre capacity at `NTP` The gases are made to combine to form water . The weight of water formed .
A
`7.03 xx 10^(-1) g`
B
`8.03 xx 10^(-2) g`
C
`8.03 xx 10^(-1) g`
D
`7.03 xx 10^(-2) g`
Text Solution
Verified by Experts
At `NTP` the moles of `H_(2)O` formed =mole of `H_(2)` `=(PV)/(RT)=(1xx1)/(0.0821 xx273) =4.46 xx 10^(-2)` `:.` wt of `H_(2)O` formed ` =4.46 xx 10^(-2) xx18` ` = 8.03 xx 10^(-1) g` .
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