When 3.725g of KCl is dissolved in exces...

When `3.725g` of `KCl` is dissolved in excess of water, the amount of heat absorbed is `X` `Kj`. Calculate the enthalpy of solution of `KCl`.

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`KCl+aq. rarr KCl_((aq.)),DeltaH=?`
`:' 3.725g KCl` on dissolution absorbed heat `=X kJ`
`:. 74.5g KCl` on dissolution absorbed heat
`=(X(74.5))/(3.725)=20X`
`:. KCl+aq. rarr KCl_((aq.)),DeltaH=20X`

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