`62.5 xx 10^(18)` electrons per second are flowing through a wire of area of cross-section `0.1 m^(2)`, the value of current flowing will be

Options

A. `1 A`
B. `0.1 A`
C. `10 A`
D. `0.11 A`

Explanation

To find the current flowing through the wire when `62.5 x 10^(18)` electrons are flowing per second, we can follow these steps:

### Step 1: Understand the relationship between current, charge, and time
The current \( I \) is defined as the rate of flow of charge. Mathematically, it can be expressed as:
\[ I = \frac{Q}{T} \]
where \( Q \) is the charge and \( T \) is the time.

### Step 2: Calculate the total charge flowing per second
The total charge \( Q \) can be calculated using the formula:
\[ Q = N \cdot e \]
where:
- \( N \) is the number of electrons flowing per second (in this case, \( N = 62.5 \times 10^{18} \)),
- \( e \) is the charge of a single electron, which is approximately \( 1.6 \times 10^{-19} \) coulombs.

### Step 3: Substitute the values into the charge formula
Now we can substitute the values into the charge formula:
\[ Q = (62.5 \times 10^{18}) \cdot (1.6 \times 10^{-19}) \]

### Step 4: Perform the multiplication
Calculating the product:
\[ Q = 62.5 \times 1.6 \times 10^{18} \times 10^{-19} \]
This simplifies to:
\[ Q = 100 \times 10^{-1} = 10 \text{ coulombs} \]

### Step 5: Calculate the current
Since the time \( T \) is given as 1 second, we can now calculate the current:
\[ I = \frac{Q}{T} = \frac{10 \text{ coulombs}}{1 \text{ second}} = 10 \text{ amperes} \]

### Final Answer
The value of the current flowing through the wire is:
\[ \boxed{10 \text{ A}} \]