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In hydrogen atom, when electron jupms fr...

In hydrogen atom, when electron jupms from second to first orbit, then enrgy emitted is

A

`-13.6 eV`

B

`-27.2 eV`

C

`-6.8 eV`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(n_(1)rarrn_(2)) =- 13.6 [(1)/(n_(2)^(2)) - (1)/(n_(1)^(2))], n_(1) = 2` and `n_(2) = 1`
`rArr E_(II) rarr E_(I) =- 13.6 xx (3)/(4) =- 10.2 eV`
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Knowledge Check

  • In hydrogen atom, when electron jumps from second to first orbit, then energy emitted is

    A
    `-13.6 eV`
    B
    `-27.2eV`
    C
    `-6.8 eV`
    D
    None of these

  • When the elecrton in the hydrogen atom jupms from 2nd orbit to 1st orbit, the wavelength of radiation emitted is lambda . When the electrons jupms from 3rd orbit to 1st orbit, the wavelength of emitted radiation would be

    A
    `(27)/(32) lambda`
    B
    `(32)/(27) lambda`
    C
    `(2)/(3) lambda`
    D
    `(3)/(2) lambda`

  • The wavelength of radiation emitted is lamda_0 when an electron in a hydrogen atom jumps from 3rd to 2nd orbit . If the same hydrogen atom , the electron jumps from 4th orbit to 2nd orbit , then the wavelength of the emitted radiation will be

    A
    `10/25 lamda_0`
    B
    `25/16 lamda_0`
    C
    `27/20 lamda_0`
    D
    `20/27 lamda_0`
    • A2Z-ATOMIC PHYSICS-Section D - Chapter End Test
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