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In the circuit shown, R is a pure resist...

In the circuit shown, `R` is a pure resistor, `L` is an inductor of negligible resistance (as compared to `R`) and `S` is a`100V,50 Hz AC` source of negligible resistance. With eigther key `k_(1)` alone or `k_(2)` alone closed, the current is `I_(0)`. if the source is changed to `100 V, 100 Hz`, the current with `k_(1)` alone closed and with `k_(2)` alone closed will be respectively

A

`I_(0),1/2I_(0)`

B

`2I_(0),1/2I_(0)`

C

`2I_(0),I_(0)`

D

`2I_(0),1/2I_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A

With change in frequency resistance will not change but inductive reactance is reduced to half.
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